Homeworks | |
All homeworks are available at the envelope near room 646 |
פורסם ב-10/4/2007, 09:04:17 Created on 10/4/2007, 09:04:17 Создано10/4/2007, 09:04:17 تم النشر ب-10/4/2007, 09:04:17 |
תרגיל בית 4 Homework 4 Homework 4 Homework 4 | |
The grades are online. One couple of students didn't submit their homework yet, so I didn't put the checked homeworks at the boxes. If you want to see your homework before I check all homeworks, contact me Anna |
פורסם ב-20/3/2007, 20:36:07 Created on 20/3/2007, 20:36:07 Создано20/3/2007, 20:36:07 تم النشر ب-20/3/2007, 20:36:07 |
תרגיל בית 4 Homework 4 Homework 4 Homework 4 | |
Errors in first question are fixed. Please download homework again |
פורסם ב-21/2/2007, 12:59:12 Created on 21/2/2007, 12:59:12 Создано21/2/2007, 12:59:12 تم النشر ب-21/2/2007, 12:59:12 |
תרגיל בית 4 Homework 4 Homework 4 Homework 4 | |
Q2 - draw tree as shown in class, but compute probabilities only for 3 different vectors |
פורסם ב-11/2/2007, 12:02:56 Created on 11/2/2007, 12:02:56 Создано11/2/2007, 12:02:56 تم النشر ب-11/2/2007, 12:02:56 |
HW 4 | |
Homework 4 is available online |
פורסם ב-5/2/2007, 13:23:25 Created on 5/2/2007, 13:23:25 Создано5/2/2007, 13:23:25 تم النشر ب-5/2/2007, 13:23:25 |
HW 2 | |
Homework 2 weight will be less then other homeworks in the final grade Solution to the question 1 part 1 1. If N = 0, no crossovers have occured. If N = 1, one crossover has occured, i.e. the meiosis results in two recombinant and two non-recombinant haplotypes. This means that a recombinant haplotype will be transmitted with probability 0.5. Assume for N = k that the recombination probability is 0.5. This means that two of the chromtids are recombinant and two are nonrecombinant, i.e. a chromatid is recombinant with probability 0.5. Now if an additional crossover occurs (N = k +1), it will occur between two non-recombinant chromatids with probability 0.25, yielding four recombinant haplotypes. With probability 0.5, it will occur between a non- recombinant and a recombinant chromatid, yielding two recombinant haplotypes. With probability 0.25, it will occur between two recombinant chromatids, i.e. no recombinant haplotypes. Hence, the probability of transmission of a recombinant haplotype is 0.25 * 1+ 0.5 * 0.5 + 0.25*0 = 0.5 Thus, the recombination probability is 0.5 for all positive integers N |
פורסם ב-11/1/2007, 15:51:12 Created on 11/1/2007, 15:51:12 Создано11/1/2007, 15:51:12 تم النشر ب-11/1/2007, 15:51:12 |
HW 3 | |
HW3 1. Q2 - The intention was IBD, but if you have already written solution with IBS it's ok. 2. Q7 P(A=a) = Σ{A=a,B,C,D,E,F} P(A,B,C,D,E,F,G,H) |
פורסם ב-11/1/2007, 15:49:24 Created on 11/1/2007, 15:49:24 Создано11/1/2007, 15:49:24 تم النشر ب-11/1/2007, 15:49:24 |
HW3 | |
Homework 3 is now available |
פורסם ב-28/12/2006, 15:48:47 Created on 28/12/2006, 15:48:47 Создано28/12/2006, 15:48:47 تم النشر ب-28/12/2006, 15:48:47 |
HW2 | |
Submition postponed till 1/1/2007 |
עדכון אחרון ב-15/12/2006, 08:39:18 Last updated on 15/12/2006, 08:39:18 Последняя модификация15/12/2006, 08:39:18 تمت الحتلنة الأخيرة ب-15/12/2006, 08:39:18 |
Changes | |
On 23/11 there will be two hours tutorial instead of lecture On 30/11 there will be three hours lecture |
פורסם ב-22/11/2006, 10:36:57 Created on 22/11/2006, 10:36:57 Создано22/11/2006, 10:36:57 تم النشر ب-22/11/2006, 10:36:57 |
Welcome to course 236633 - Advanced Topics in Bioinformatics | |
Our website is at http://www.cs.technion.ac.il/~anna_bi/cs236633/ |
פורסם ב-7/11/2006, 23:23:45 Created on 7/11/2006, 23:23:45 Создано7/11/2006, 23:23:45 تم النشر ب-7/11/2006, 23:23:45 |